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(5\2)³ ÷ (125\8)^1\6 =
125\8 * 8\125 ^ -6 = 1^ -6 =1 ( skracamy 125 \125 i 8\8)
y=^6√36³ =[(36)³]^1\6=
=[(6² )³ ]^1\6 =(6^6) ^1\6 =6^1 =6
Czyli Y jest większe.