December 2018 1 73 Report
Ktoś mi może wyjaśnić skąd wzięło się takie rozwiązanie?
 \lim_{n \to\ 0 } \frac{2^x-1}{3^x-1}=[ \frac{0}{0}]= \lim_{n \to \ 0} \frac{2^x-1}{x}* \frac{x}{3^x-1}= \frac{ln2}{ln3}
More Questions From This User See All

Recommend Questions



Life Enjoy

" Life is not a problem to be solved but a reality to be experienced! "

Get in touch

Social

© Copyright 2013 - 2025 KUDO.TIPS - All rights reserved.