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(2sinα -3cosα)/(sinα + cosα)= (2sinα - 3·3sinα)/ (sinα + 3sinα)=
(2sinα - 9sinα)/ (4sinα) = -7sinα/ 4sinα= -7/4
W wyrażeniu cosα zastępujemy 3sinα, a potem skracamy przez sinα.