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sinα/cosα = 3 /*cosα
sinα = 3cosα /()²
sin²α = 9cos²α
Korzystam ze wzoru na jedynkę trygon.
sin²α + cos²α = 1
9cos²α + cos²α = 1
10cos²α = 1 /:10
cos²α = 1/10 /:√
cosα = 1 / √10
cosα = √10/10
sinα = 3*√10 /10
sinα = 3√10/10
sinα + cosα = √10 / 10 + 3√10 / 10 = 4√10/10 = 2√10/5