Zad 9/24 Matematyka z plusem 2
c) 2^9 : (-6^7 : 3^7)
f) 25^2 x 4^7 / 2^9 x 5^4
g) 2^10 x 3^10 / 6^8
h) 5^8 x 2^9 / 10^7
^ - do potęgi
x - mnożenie
/ -kreska ułamkowa
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c) 2^9 : (-6^7 : 3^7)=![2^9:(-6:3)^7=2^9:(-3)^7=512:(-2187)= 2^9:(-6:3)^7=2^9:(-3)^7=512:(-2187)=](https://tex.z-dn.net/?f=2%5E9%3A%28-6%3A3%29%5E7%3D2%5E9%3A%28-3%29%5E7%3D512%3A%28-2187%29%3D)
f) 25^2 x 4^7 / 2^9 x 5^4=![\frac{5^4*2^{14}}{2^9*5^4}=\frac{2^{14}}{2^9}=2^{14-9}=2^5 \frac{5^4*2^{14}}{2^9*5^4}=\frac{2^{14}}{2^9}=2^{14-9}=2^5](https://tex.z-dn.net/?f=%5Cfrac%7B5%5E4%2A2%5E%7B14%7D%7D%7B2%5E9%2A5%5E4%7D%3D%5Cfrac%7B2%5E%7B14%7D%7D%7B2%5E9%7D%3D2%5E%7B14-9%7D%3D2%5E5)
g) 2^10 x 3^10 / 6^8=![\frac{6^{10}}{6^8}=6^{10-8}=6^2 \frac{6^{10}}{6^8}=6^{10-8}=6^2](https://tex.z-dn.net/?f=%5Cfrac%7B6%5E%7B10%7D%7D%7B6%5E8%7D%3D6%5E%7B10-8%7D%3D6%5E2)
h) 5^8 x 2^9 / 10^7
czy c i h masz dobrze napisane ?