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3(x+2)² - 2(x-2)² < x²
3(x²+4x+4) - 2(x²-4x+4) <x²
3x²+12x+12-2x²+8x-8 <x²
3x²+12x-2x²+8x-x² < 8-12
20x < -4 //:20
x < -0,2
odp: najmniejsza bd -1 a najwieksza bd minus nieskonconosc