Question

Kordinat fokus elips x"+2y"+4x-4y+2=0 adalah.
jawab+caranya

Answer 1

X^2+2y^2+4x-4y+2=0
(x^2+4x)+(2y^2-4y) = -2
(x^2+4x+4)+2(y^2-2y+1) = -2+4+2
(x+2)2-2(y-1)2 = 4
(x+1)^2/2 - (y-1)^2/1 = 1
a^2 = 2, b^2= 1
c = akar 2+1
= akar 3
p = -1, q = 1
F (-1-akar3, 1) & (-1+akar3, 1)