Koło roweru ma średnicę 40 cm . Ile obrotów wykona to koło na drodze 3km (przyjmij π≈3)?
d=40cm
r=40cm:2=20cm
l=2πr
l=2*3*20cm=120cm
3km=3000m=300000cm
300000cm:120cm=2500
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d=40cm
r=40cm:2=20cm
l=2πr
l=2*3*20cm=120cm
3km=3000m=300000cm
300000cm:120cm=2500