Diketahui:
f'(x) = 2(3x²-1)
f(-1) = 5
Ditanyakan:
f(2)
Jawab:
f(x) = ∫ f'(x) dx
= ∫ 2(3x²-1) dx
= 2 ∫ 3x²-1 dx
= 2 (3(1/(2+1))x^(2+1)-(1/(0+1))1x^(0+1))
= 2 (3(1/3)x³-x)
= 2(x³-x)
= 2x³-2x+C
f(-1) = 2(-1)³-2(-1)+C
5 = -2+2+C
5 = C
f(x) = 2x³-2x+5
f(2) = 2(2)³-2(2)+5
= 2(8)-4+5
= 16-4+5
= 17 (B)
Mapel: Matematika
Kelas: 11
Materi: Turunan
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Diketahui:
f'(x) = 2(3x²-1)
f(-1) = 5
Ditanyakan:
f(2)
Jawab:
f(x) = ∫ f'(x) dx
= ∫ 2(3x²-1) dx
= 2 ∫ 3x²-1 dx
= 2 (3(1/(2+1))x^(2+1)-(1/(0+1))1x^(0+1))
= 2 (3(1/3)x³-x)
= 2(x³-x)
= 2x³-2x+C
f(-1) = 2(-1)³-2(-1)+C
5 = -2+2+C
5 = C
f(x) = 2x³-2x+5
f(2) = 2(2)³-2(2)+5
= 2(8)-4+5
= 16-4+5
= 17 (B)
Mapel: Matematika
Kelas: 11
Materi: Turunan