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Ralat soal → 8 cos 2x
t = 1/2 x → x = 2t
cos 2x = cos 4t = 1 - 2 sin² 2t
••
8 cos 2x + 6 sin x - 7 = 0
8(1 - 2 sin² 2t) + 6 sin 2t - 7 = 0
16 sin² 2t - 6 sin 2t - 1 = 0
(8 sin 2t + 1)(2 sin 2t - 1) = 0
sin 2t = -1/8 → kuadran 3 dan 4 → tdk memenuhi interval
2 sin 2t - 1 = 0
sin 2t = 1/2
2t = 30° + k.360°
t = 15° + k.180°
atau
2t = 150° + k.360°
t = 75° + k.180°
k bilangan bulat
Nilai t yg memenuhi interval 0° ≤ x ≤ 180° :
15° dan 75°
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Verified answer
•
Ralat soal → 8 cos 2x
t = 1/2 x → x = 2t
cos 2x = cos 4t = 1 - 2 sin² 2t
••
8 cos 2x + 6 sin x - 7 = 0
8(1 - 2 sin² 2t) + 6 sin 2t - 7 = 0
16 sin² 2t - 6 sin 2t - 1 = 0
(8 sin 2t + 1)(2 sin 2t - 1) = 0
sin 2t = -1/8 → kuadran 3 dan 4 → tdk memenuhi interval
2 sin 2t - 1 = 0
sin 2t = 1/2
2t = 30° + k.360°
t = 15° + k.180°
atau
2t = 150° + k.360°
t = 75° + k.180°
k bilangan bulat
Nilai t yg memenuhi interval 0° ≤ x ≤ 180° :
15° dan 75°