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Verified answer
ΔABC sama kakiAB = √[(-2 - ½)² + (-2 - 5)²]
AB = √(25/4 + 49)
AB = √221 / 2
BC = √[(3 + 2)² + (-2 - 2)²]
BC = √(25 + 16)
BC = √41
AC = √[(3 - ½)² + (-2 - 5)²]
AC = √(25/4 + 49)
AC = √221 / 2
Karena AB + BC
= 2 • (√221 / 2) > √41
Maka ABC membentuk segitiga
Karena AB = AC , ΔABC adalah segitiga sama kaki