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(k+1)b+2k=c
kb+b+2k=c
kb+2k=c-b
k(b+2)=c-b|:(b+2)
k=c-b/b+2
f/1=k+1/k+2
f(k+2)=1(k+1)
fk+2f=k+1
fk-k=1-2f
k(f-1)=1-2f|:(f-1)
k=1-2f/f-1
g/1=2-1/k
gk=2-1|:g
k=2-1/g
h=ka2+k
ka2+k=h
k(a2+1)=h|:(a2+1)
k=h/a2+1
i=a/2+2/k
a/2+2/k=i
a+k=i
k=i-a