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a = 12 , b = 3 dan Un = 99
Un = a + (n-1)b
99 = 12 + (n-1)3
99 =12 + 3n - 3
3n = 90 ⇔ n = 90/3 = 30
Sn = (n/2)(a+Un)
S30 = (30/2)(12 + 99)
= 15(111)
= 1665
Jadi, jumlah bilangan antara 10 s.d 100 yang habis dibagi 3 adalah 1665