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Verified answer
Semoga paham yaa :))Verified answer
Misal :(√5)^x = a
a² = 5^x
5^x - 6(√5)^x + 5 = 0
a² - 6a + 5 = 0
a1 . a2 = c/a = 5
(√5)^x1 . (√5)^x2 = 5
(√5)^(x1 + x2) = 5
5^((x1 + x2)/2) = 5
(x1 + x2)/2 = 1
x1 + x2 = 2