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2x + y = 1 => y = -2x + 1
y = y
-2x + 1 = x^2 + px + 5
x^2 + px + 2x + 5 - 1 = 0
x^2 + (p+2)x + 4 = 0
a = 1 ; b = (p+2) c =4
D = 0
b^2 - 4ac = 0
(p+2)^2 - 4.1.4 = 0
p^2 + 4p + 4 - 16 = 0
p^2 + 4p - 12 = 0
(p+6)(p-2) = 0
p = -6 atau p = 2
maka p yang memenuhi p = 2