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(y') (sin 90 cos 90)(y -4) (4)
(x') = (0 -1)(x-2) + (2)
(y') (1 0)(y-4) (4)
(x') = 4-y+2 = 6 - y
(y') x-2+4 = x+2
dari x' = 6 - y didapat y = 6-x'
dari y' = x+2 didapat x = y'-2
subsitusikan ke persamaan garisnya
x - 3y = 5
(y'-2) -3(6-x') = 5
y' - 2 + 18 + 3x' = 5
3x + y = - 11 atau
3x + y + 11 = 0