Question

Untuk menentukan gambar tersebut, bagaimana caranya ya kak? thnks yaa((:

Answer 1

Kita cari titik potong kedua kurva sebagai batas integral nya
y = y
x^2 = x + 2
x^2 - x - 2 = 0
(x - 2)(x + 1) = 0
x = 2 atau x = -1
Jadi
V = π int [(x + 1)^2 - (x^2)^2] dx
= π int [(x + 1)^2 - x^4] dx
= [(1/3)(x + 1)^3 - (1/5)x^5] π => batas -1 sampai 2
= [ (1/3)(2 + 1)^3 - (1/5)(2)^5 ] - [ (1/3)(-1 + 1)^3 - (1/5)(-1)^5 ] π
= [ 9 - 32/5 ] - [ 0 + 1/5] π
= (9 - 32/5 - 1/5)π
= (9 - 33/5)π
= (12/5) π
= 2 2/5 π