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x1 = 3 => f(x1) = 3
x2 = 3 - (1/2) = 5/2 => f(x2) = 5/2
x3 = 5/2 - 1/2 = 2 => f(x3) = 2
x4 = 2 - 1/2 = 3/2 => f(x4) = 3/2
x5 = 3/2 - 1/2 = 1 => f(x5) = 1
x6 = 1 - 1/2 = 1/2 => f(x6) = 1/2
Sigma f(xi) = 3 + 5/2 + 2 + 3/2 + 1 + 1/2 = 6 + 9/2 = 21/2
Jumlah rieman = sigma f(xi) . ∆x = 21/2 . 1/2 = 21/4