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f(1) = 3
f(1) = a(1)^2 + b(1) + c = 3
f(1) = a + b + c = 3
f(-1) = a(-1)^2 + b(-1) + c = 3
f(-1) = a - b + c = 3
a+b+c = 3
a-b+c = 3
2a + 2c = 6
2(a+c) = 6
a+c = 3
jadi,a+c = 3
f(1) = a(1)^2 + b(1) + c = 3 ... (1)
f(-1) = a(-1)^2 + b(-1) + c = 3
f(-1) = a - b + c = 3 ... (2)
eliminasi persamaan 1 dan 2
a + b + c = 3
a - b + c = 3
2b = 3
b = 3/2.
substitusi nilai b ke persamaan 1.
a + b + c = 3
a + c = 3 - b
a + c = 3 - 3/2
a + c = 6/2 - 3/2
a + c = 3/2.