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f(2) = 1---> 2a +b = 1
kurankan --> =a = 1 --> a = -1
b = 2 - a --> b = 2 - (-1) = 3
a) f(x) = -x + 3
b) f(x-1) = -(x-1) + 3 --> f(x) = x +1+3 = x + 4
c) f(x) + f(x-1) = (-x +3) + [ -(x-1) + 3]
= -x + 3 - x+1 + 3
= 7
f(2) = 1 ---> 2a +b = 1
f(1) = 2 ---> a + b = 2
------------------------------------ -
a = -1
subsitusikan a = -1 ke a+b = 2
a+ b = 2
-1 + b = 2
b = 2+1
b = 3
a) f(x) = ax + b
= -x + 3
b) f(x-1) = -(x-1) + 3
= -x +1+3
= -x + 4
c) f(x) + f(x-1) = (-x +3) + (-x+4)
= -x + 3 - x+ 4
= -2x + 7