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mmol NH4OH = 200 x 0,35 = 70 mmol
HCl + NH4OH => NH4Cl + H2O
a : 75 70
b : 70 70 70 70
s : 5 - 70 70
[HCl] = 5 mmol / (300 ml+200 ml) = 0,01 M
[H+] = [HCl] = 0,01 M = 10⁻² M
pH = - log [H+]
pH = - log 10⁻²
pH = 2