Question

Quiz KIMIA Kelas X SMA
Bab Stokiometri

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Answer 1

Verified answer

N Fe₂O₃ = 7000 g / 160 g/mol = 43.75 mol
n CO = 3000 g / 28 g/mol = 750 / 7 mol
   Fe₂O₃ + 3CO ⇒ 2Fe  +  3CO₂
m 43.75    750/7
b  750/21  750/7    1500/21 750/7 
s  8.0357      -         1500/21 750/7

n Fe = 1500/21 mol
gr Fe = n Fe . Ar Fe = 1500/21 . 56 = 4000 g = 4 kg

gr Fe₂O₃ (sisa) = n Fe₂O₃ . 160 = 1285.71 g = 1.286 kg ⇒ Jawab