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s = √108
s = 6√3 cm
HAC membentuk segitiga sama sisi dengan sisi = 6√6 cm
jarak H ke AC = √((6√6)² - (3√6)²)
= √(216 - 54)
= √162 cm
= 9√2 cm
2. ∫ (s² - 4s)s ds
= ∫ (s³ - 4s²) ds
= (1/4)s⁴ -(4/3)s³ + C