Jak rozwiązać (x-1)do potęgi2 +7>(x+4)do potęgi 2
(x-1)²+7> (x+4)²
x²-2x+1+7-x²-8x-16>0
-10x>8 /:(-10)
x < -0,8
x∈(-∞;-0,8)
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(x-1)²+7> (x+4)²
x²-2x+1+7-x²-8x-16>0
-10x>8 /:(-10)
x < -0,8
x∈(-∞;-0,8)