jak rozwiązać ( 3 i 3/8 do potęgi minus dwie trzecie
(3i3/8)^-2/3=
=1/(27/8)^2/3=
=1/(∛(27/8))^2 =
=1/(∛(3^3/2^3))^2 =
=1/(∛(3/2)^3)^2 =
=1/(3/2)^2 =
=(2/3)^2 = 4/9
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(3i3/8)^-2/3=
=1/(27/8)^2/3=
=1/(∛(27/8))^2 =
=1/(∛(3^3/2^3))^2 =
=1/(∛(3/2)^3)^2 =
=1/(3/2)^2 =
=(2/3)^2 = 4/9