jak obliczyc w tym działaniu d1 ? d1* (d1-2)=40cm2 please pomocy
ale tak logicznie proszę
d₁(d₁-2) = 40
d₁²-2d₁-40 = 0
Δ = b²-4ac = 4+160 = 164
√Δ = √164 = 2√41
d₁ = (-b+√Δ)/2 = (2+2√41)/2 = 1+√41
d₁ = 1+√41 cm
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d₁(d₁-2) = 40
d₁²-2d₁-40 = 0
Δ = b²-4ac = 4+160 = 164
√Δ = √164 = 2√41
d₁ = (-b+√Δ)/2 = (2+2√41)/2 = 1+√41
d₁ = 1+√41 cm