Jak długo spadało by ciało z wysokości 6m . Jeżeli spada zgodnie z zasadami grawitacji
h = 6 m
g = 9,81 m/s²
t = ?
h = (gt²) / 2
2h = gt²
t² = (2h) / g
t = √[(2h) / g]
t = 1,11 s
s=g*t^2 /2
2s=g*t^2
t^2=2s/g
t=pierwiastek z 2s/g
t=1.11s
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h = 6 m
g = 9,81 m/s²
t = ?
h = (gt²) / 2
2h = gt²
t² = (2h) / g
t = √[(2h) / g]
t = 1,11 s
s=g*t^2 /2
2s=g*t^2
t^2=2s/g
t=pierwiastek z 2s/g
t=1.11s