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F(x) = ax + bf(2) => 2a + b = 2 ... [i]
f(3) => 3a + b = 5 ... [ii]
Eliminasi ii dengan i
3a + b = 5
2a + b = 2
––––––––– (–)
a = 3
Subs. a = 3 ke 2a + b = 2
2(3) + b = 2
b = -4
f(x) = 3x - 4
Untuk x = 9
f(9) = 3(9) - 4 = 23