Ile wazy w warunkach normalnych 1,12dm3 N2?
o co tu chodzi?
mN2=28u
28g azotu------22,4dm3
xg azotu--------1,12dm3
x = 1,4g
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mN2=28u
28g azotu------22,4dm3
xg azotu--------1,12dm3
x = 1,4g