Ile trzeba wziąść 30% -owego roztworu kwasu , a ile 60%-owego ,aby po zmieszaniu otrzymać 200g , 40%
60% 40-30=10
40%
30% 60-40=20
m1:m2 = 10:20 = 1:2
mr3 = 200g
mr1 + mr2 = mr3
1x + 2x = 200
3x = 200
x = 66,7
m1 = 66,7g
m2 = 2 * 66,7g = 133,4 g
x- 30% roztwór kwasu
y-60% roztwór
x+y=200
30%x+60%y=200*40%
0,3x+0,6y=200*0,4
x+y=200/*-3
0,3x+0,6y=80/*10
-3x-3y=-600
3x+6y=800
---------------
3y=200/3
y=66 2/3
x=200-66 2/3
x=133 1/3
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60% 40-30=10
40%
30% 60-40=20
m1:m2 = 10:20 = 1:2
mr3 = 200g
mr1 + mr2 = mr3
1x + 2x = 200
3x = 200
x = 66,7
m1 = 66,7g
m2 = 2 * 66,7g = 133,4 g
x- 30% roztwór kwasu
y-60% roztwór
x+y=200
30%x+60%y=200*40%
x+y=200
0,3x+0,6y=200*0,4
x+y=200/*-3
0,3x+0,6y=80/*10
-3x-3y=-600
3x+6y=800
---------------
3y=200/3
y=66 2/3
x=200-66 2/3
x=133 1/3