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1mol - 6,02 * 10²³ cz
x moli-120,63 x 10¹⁸
x = (120,63 x 10¹⁸ * 1mol)/6,02 * 10²³ ≈ 20 * 10⁻⁵
2. 180 cm sześciennych azotu
V= 180 cm³ = 0,18 dm³
1mol - 22,4 dm³
x moli-- 0,18 dm³
x= 0,18 dm³ * 1mol / 22,4dm³ ≈ 0,008 mola