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112 ...........80.....32
112 - 32
15 - X
X = 4,28
Odp. Z 15 g tlenku powstanie 4,28 g tlenu.
2CaO=2Ca+O2;
M CaO=40[g/mol]+16[g/mol]=56[g/mol];
M O2=2*16[g/mol]=32[g/mol];
Układamy proporcję:
112[g]CaO - 32[g]O2;
15[g]CaO - x[g]O2;
x=4,3[g]O2.
Odp.Powstanie 4,3[g]O2.