Ile gramów metanolanu potasu znajduje się w 3dm3 półmolowego roztworu ?
Cm=0,5mol/dm³
Vr=3dm³
M(CH₃OK)=12g/mol+3*1g/mol+16g/mol+39g/mol=70g/mol
n=?
ms=?
Cm=n/Vr /*Vr
n=Cm*Vr
n=0,5mol/dm³ * 3dm³
n=1,5mol
n=ms/M /*M
ms=n*M
ms=1,5mol*70g/mol
ms=105g
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Cm=0,5mol/dm³
Vr=3dm³
M(CH₃OK)=12g/mol+3*1g/mol+16g/mol+39g/mol=70g/mol
n=?
ms=?
Cm=n/Vr /*Vr
n=Cm*Vr
n=0,5mol/dm³ * 3dm³
n=1,5mol
n=ms/M /*M
ms=n*M
ms=1,5mol*70g/mol
ms=105g