ile gramow innych metali nalezy dodac do 3g czystego srebra,aby otrymac stop proby 0,800 ?
3/( 3 + x) = 0,800
3/( 3 + x) = 8/10 = 4/5
(3 + x)*4 = 3*5
12 + 4x = 15
4x = 15 - 12 = 3 / : 4
x = 3/4 =0,75
Odp. Trzeba dodać 0,75 g innych metali.
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3/( 3 + x) = 0,800
3/( 3 + x) = 8/10 = 4/5
(3 + x)*4 = 3*5
12 + 4x = 15
4x = 15 - 12 = 3 / : 4
x = 3/4 =0,75
Odp. Trzeba dodać 0,75 g innych metali.