Question

Ile dm3 chlorowodoru (warunki normalne) potrzeba do zobojętnienia 50g 1% roztworu wodorotlenku wapnia?

Answer 1

M(Ca(OH)₂)=40g+2*16g+2*1g=74g

mr=50g

Cp=1%

 

ms=?

V(HCl)=?

 

Cp=ms/mr * 100%    /*mr

Cp*mr=ms*100%       /:100%

ms=Cp*mr/100%

 

ms=1%*50g/100%

ms=0,5g 

 

 

Ca(OH)₂+2HCl-->CaCl₂+2H₂O

0,5g-------xdm³

74g--------2*22,4dm³

 

x=0,5g*44,8dm³/74g

x=0,3dm³

Answer 2

 

 

2*22,4dm³--74g

2HCl+ Ca(OH)₂--> CaCl₂+ 2H₂O

x------0,5g

 

x= 0,5g*2*22,4dm³/ 74g

x= 0,3dm³ HCl