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mO₂=32u
2N₂ + 5O₂ ---> 2N₂O₅
2*22,4dm³ azotu ---- 2mole tlenku
xdm³ azotu ----------- 5moli tlenku
x = 112dm³ azotu
5*32g tlenu ---- 2mole tlenku
xg tlenu -------- 5moli tlenku
x = 400g tlenu
2)
mAl₂O₃=150u
2Al₂O₃ + 3C ---> 4Al + 3CO₂
2*150g Al₂O₃ ------ 3*22,4dm³ CO₂
1g Al₂O₃ ---------- xdm³ CO₂
x = 0,224dm³ CO₂