Question

Hitunglah pH berikut :
Larutan 500 mL amonia 0,1 M (kb = 4.10min5)

Answer 1

Amonia merupakan basa lemah
[OH⁻] = √(Kb . M)
         = √(4 . 10⁻⁵ . 0,1) = 2 . 10⁻³
pOH = - log (2.10⁻³)
       = 3 - log 2
pH = 14 - pOH
pH = 14 - (3 - log2)
pH = 11 + log2