Question

Berapa gram zat terlarut dalam 2 liter CH3COOH (mr =60) dengan harga ph =3 (ka = 10^-5)......^pangkat min 5

Answer 1

PH = 3
[H+]= 1 x10^-3
[H+]= akar ka x M  ch3cooh
[h+]^2= ka x M ch3cooh
(1 x 10^-3)^2= 10^-5 x M ch3cooh
M ch3cooh = 0,1 M

M= n /v
n= M x v
  =0,1 x 2 = 0,2 mol

n= m/mr
m=mr x n = 60 x 0,2 = 12 gram