Question

Hitung differensial -1

Turunan pertama dari y = (1-x)²(x+2) adalah ...

Answer 1

Y = (1 - x)²(x + 2)
y'= 2(1 - x)(-1)(x + 2) + (1 - x)²(1)
   = -2(1-x)(x+2) + 1-2x + x²
   = -2(x + 2 - x² - 2x) + 1-2x+x²
   = -2x -4 +2x² + 4x + 1 - 2x + x²
  = 3x² - 3
jadi turinannya y' = dy/dx = 3x² - 3

Answer 2

y = (1-x)²(x+2)
y' = u'v + uv'
= -2(1-x)(x+2) + (1-x)^2 . 1
= 2 (x-1)(x+2) + 1-2x+x^2
= 2 (x^2 +x -2) + 1 -2x +x^2
= 2x^2 +2x -4 +1 -2x +x^2
=3x^2 -3