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log 2 [log (x+3)] = log (log 16x²)
log log(x+3)² = log log(16x²)
(x+3)² = 16x² dengan pembatas x+3 > 0 ∩ 16x²> 0
(x+3) = +-√(16 x²) , batas x> - 3 ∩ x > 0
x+ 3 = 4x atau x+3 = - 4x. dgn batas x > 0
x - 4x = - 3 atau x+ 4x = - 3 , batas x > 0
-3x = -3 atau 5x = - 3, batas x > 0
x = 1 atau x= - 3/5, batas x > 0
maka
hp x = 1