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log x² = log 3(x+6)
x² = 3(x+6) dengan batas x >0 ∩ x + 6 > 0 --> x > 0
x²- 3x - 18 = 0
(x - 6)(x+3)= 0
x = 6 atau x = - 3
krn x > 0 ,maka x = 6