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U2=5.500.000
U3=6.000.000
b=U2-U1=500.000
dit: jumlah tabungan akhir tahun/S12 ?
Sn=n/2[2a+(n-1)b]
Sn=12/2[2x5.000.000+(12-1)500.000]
=6(15.500.000)
=93.000.000