y'=y/(x+√(xy) )
= (y/x)/(1+√(y/x) )
misal y=vx
dy=vdx+xdv
terusin sendiri seperti yg sudah saya jawab
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y'=y/(x+√(xy) )
= (y/x)/(1+√(y/x) )
misal y=vx
dy=vdx+xdv
terusin sendiri seperti yg sudah saya jawab