Question

Hasil dari xy' - y = x

Answer 1

xy' - y = xe^{y/x}

xy' =x e^{y/x} +y

y' = e^{y/x} +y/x

dy= (e^{y/x} +y/x)dx

misal

y=vx

dy=vdx+xdv

vdx+xdv= (e^v+v)dx

xdv- e^vdx=0

e^-vdv- 1/xdx=0

-e^-v-lnx=c

-e^(-y/x)-lnx=c