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V=54[km/h]/3,6=15[m/s];
F=4[kN]=4000[N];
szukamy:
P=?[W]-watów;
Wzór:
P=W/t;W=F*s;V=s/t;
P=(F*s)/t;
P=F*V;
Jednostka:
[P]=[N*(m/s)]=[J/s]=[W];
Obliczynia:
P=4000*15=60000[W]=60[kW].
Odp.Moc silnika autobusu wynosi P=60[kW].