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f(1)=√3
lim √2h+3 +√3/h h→0
multiplicando arriba y abajo por la conjugada
(√2h+3 +√3)(√2h+3 -√3)/h(√2h+3 -√3)
2h/h(√2h+3 -√3)
2/(√2h+3 -√3)
evaluando en 0
1/√3 )√3/3