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[√(x+h)-√x]/h . [√(x+h)+√x] / [√(x+h)-√x] (diferencia de cuadrados)
= [x+h-x] / {h [√(x+h)+√x]} = 1 / [√(x+h)+√x]
Si h tiende a cero queda:
1 / [2 √x]
Es la derivada de √x
Saludos Herminio