Question

Funkcja liniowa ma wzór f(x)=(4p-3)x+5 . Wyznacz p, jeśli miejscem zerowym jest -1

Answer 1

 f(x)=(4p-3)x+5

 

(4p-3)x+5 = 0

(4p - 3) x = -5

x = -5 / (4p - 3)

 

 

x = -1

-5 / (4p - 3) = -1

-1 * (4p - 3) = 1 * (-5)

-4p + 3 = -5

-4p = -5 - 3

-4p = -8

p = 2 --------   odpowiedź

Answer 2

f(x) = (4p-3)x+5

(4p-3)x+5 = 0

x = -1

 

(4p-3)*(-1) = -5

-4p+3 = -5

-4p = -8  /:(-4)

p = 2

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