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f(13) = 3 - 1 = 2
f(14) = 4 - 1 = 3
f(15) = 5 - 1 = 4
f(16) = 6 - 1 = 5
.x.. | 12 | 13 | 14 | 15 | 16
f(x) | .1 | ..2 | .3 | .4 | .5
kropki tylko "ustawiają" odpowiednio znaki
Zw = {1, 2, 3, 4, 5}
jak masz pytania pisz na pw