C= caballos=4 patas
P= patos = 2patas
Si: C+P= 90 animales
4C+2P= 260 patas
Solución:
4C+2P=260
2C+2C+2P=260
2C+2(C+P)=260
2C+2(90)=260
2C+180=260
2C=260-180
2C=80
C=40
Reemplazamos:
4(40)+2P=260
160+2P=260
2P=260-160
2P=100
P=50
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x*+y= 90
4x+2y= 260
x=90-y
4(90-y)+2y=260
y=50
x=40
Solución: 40 caballos y 50 patos
C= caballos=4 patas
P= patos = 2patas
Si: C+P= 90 animales
4C+2P= 260 patas
Solución:
4C+2P=260
2C+2C+2P=260
2C+2(C+P)=260
2C+2(90)=260
2C+180=260
2C=260-180
2C=80
C=40
Reemplazamos:
4(40)+2P=260
160+2P=260
2P=260-160
2P=100
P=50